37x-16x^2=20

Solution for 37x-16x^2=20 equation:

37x-16x^2=20

We move all terms to the left:

37x-16x^2-(20)=0

a = -16; b = 37; c = -20;
Δ = b2-4ac
Δ = 372-4·(-16)·(-20)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{89}}{2*-16}=\frac{-37-\sqrt{89}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{89}}{2*-16}=\frac{-37+\sqrt{89}}{-32}
$